4x^2+4x+(x^2+x)^2=12

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Solution for 4x^2+4x+(x^2+x)^2=12 equation: 



4x^2+4x+(x^2+x)^2=12

We move all terms to the left:

4x^2+4x+(x^2+x)^2-(12)=0

We move all terms containing x to the left, all other terms to the right

4x^2+4x+(x^2+x)^2=12

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